Integrand size = 26, antiderivative size = 133 \[ \int \frac {(a+a \sec (e+f x))^3}{(c-c \sec (e+f x))^4} \, dx=\frac {a^3 x}{c^4}-\frac {8 a^3 \tan (e+f x)}{7 c^4 f (1-\sec (e+f x))^4}+\frac {4 a^3 \tan (e+f x)}{35 c^4 f (1-\sec (e+f x))^3}-\frac {62 a^3 \tan (e+f x)}{105 c^4 f (1-\sec (e+f x))^2}-\frac {167 a^3 \tan (e+f x)}{105 c^4 f (1-\sec (e+f x))} \]
[Out]
Time = 0.69 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.00, number of steps used = 19, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.346, Rules used = {3988, 3862, 4007, 4004, 3879, 3881, 3882, 3884, 4085} \[ \int \frac {(a+a \sec (e+f x))^3}{(c-c \sec (e+f x))^4} \, dx=-\frac {167 a^3 \tan (e+f x)}{105 c^4 f (1-\sec (e+f x))}-\frac {62 a^3 \tan (e+f x)}{105 c^4 f (1-\sec (e+f x))^2}+\frac {4 a^3 \tan (e+f x)}{35 c^4 f (1-\sec (e+f x))^3}-\frac {8 a^3 \tan (e+f x)}{7 c^4 f (1-\sec (e+f x))^4}+\frac {a^3 x}{c^4} \]
[In]
[Out]
Rule 3862
Rule 3879
Rule 3881
Rule 3882
Rule 3884
Rule 3988
Rule 4004
Rule 4007
Rule 4085
Rubi steps \begin{align*} \text {integral}& = \frac {\int \left (\frac {a^3}{(1-\sec (e+f x))^4}+\frac {3 a^3 \sec (e+f x)}{(1-\sec (e+f x))^4}+\frac {3 a^3 \sec ^2(e+f x)}{(1-\sec (e+f x))^4}+\frac {a^3 \sec ^3(e+f x)}{(1-\sec (e+f x))^4}\right ) \, dx}{c^4} \\ & = \frac {a^3 \int \frac {1}{(1-\sec (e+f x))^4} \, dx}{c^4}+\frac {a^3 \int \frac {\sec ^3(e+f x)}{(1-\sec (e+f x))^4} \, dx}{c^4}+\frac {\left (3 a^3\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^4} \, dx}{c^4}+\frac {\left (3 a^3\right ) \int \frac {\sec ^2(e+f x)}{(1-\sec (e+f x))^4} \, dx}{c^4} \\ & = -\frac {8 a^3 \tan (e+f x)}{7 c^4 f (1-\sec (e+f x))^4}-\frac {a^3 \int \frac {-7-3 \sec (e+f x)}{(1-\sec (e+f x))^3} \, dx}{7 c^4}+\frac {a^3 \int \frac {(-4-7 \sec (e+f x)) \sec (e+f x)}{(1-\sec (e+f x))^3} \, dx}{7 c^4}+\frac {\left (9 a^3\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^3} \, dx}{7 c^4}-\frac {\left (12 a^3\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^3} \, dx}{7 c^4} \\ & = -\frac {8 a^3 \tan (e+f x)}{7 c^4 f (1-\sec (e+f x))^4}+\frac {4 a^3 \tan (e+f x)}{35 c^4 f (1-\sec (e+f x))^3}+\frac {a^3 \int \frac {35+20 \sec (e+f x)}{(1-\sec (e+f x))^2} \, dx}{35 c^4}+\frac {\left (13 a^3\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^2} \, dx}{35 c^4}+\frac {\left (18 a^3\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^2} \, dx}{35 c^4}-\frac {\left (24 a^3\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^2} \, dx}{35 c^4} \\ & = -\frac {8 a^3 \tan (e+f x)}{7 c^4 f (1-\sec (e+f x))^4}+\frac {4 a^3 \tan (e+f x)}{35 c^4 f (1-\sec (e+f x))^3}-\frac {62 a^3 \tan (e+f x)}{105 c^4 f (1-\sec (e+f x))^2}-\frac {a^3 \int \frac {-105-55 \sec (e+f x)}{1-\sec (e+f x)} \, dx}{105 c^4}+\frac {\left (13 a^3\right ) \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{105 c^4}+\frac {\left (6 a^3\right ) \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{35 c^4}-\frac {\left (8 a^3\right ) \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{35 c^4} \\ & = \frac {a^3 x}{c^4}-\frac {8 a^3 \tan (e+f x)}{7 c^4 f (1-\sec (e+f x))^4}+\frac {4 a^3 \tan (e+f x)}{35 c^4 f (1-\sec (e+f x))^3}-\frac {62 a^3 \tan (e+f x)}{105 c^4 f (1-\sec (e+f x))^2}-\frac {a^3 \tan (e+f x)}{15 c^4 f (1-\sec (e+f x))}+\frac {\left (32 a^3\right ) \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{21 c^4} \\ & = \frac {a^3 x}{c^4}-\frac {8 a^3 \tan (e+f x)}{7 c^4 f (1-\sec (e+f x))^4}+\frac {4 a^3 \tan (e+f x)}{35 c^4 f (1-\sec (e+f x))^3}-\frac {62 a^3 \tan (e+f x)}{105 c^4 f (1-\sec (e+f x))^2}-\frac {167 a^3 \tan (e+f x)}{105 c^4 f (1-\sec (e+f x))} \\ \end{align*}
Time = 1.46 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.21 \[ \int \frac {(a+a \sec (e+f x))^3}{(c-c \sec (e+f x))^4} \, dx=\frac {a^{5/2} \tan (e+f x) \left (\sqrt {a} \sqrt {c} \left (-337+276 \sec (e+f x)+50 \sec ^2(e+f x)-396 \sec ^3(e+f x)+167 \sec ^4(e+f x)\right )-840 \text {arctanh}\left (\frac {\sqrt {-a c \tan ^2(e+f x)}}{\sqrt {a} \sqrt {c}}\right ) \sec ^3(e+f x) \sin ^6\left (\frac {1}{2} (e+f x)\right ) \sqrt {-a c \tan ^2(e+f x)}\right )}{105 c^{9/2} f (-1+\sec (e+f x))^4 (1+\sec (e+f x))} \]
[In]
[Out]
Time = 0.64 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.50
method | result | size |
parallelrisch | \(-\frac {a^{3} \left (15 \cot \left (\frac {f x}{2}+\frac {e}{2}\right )^{7}-42 \cot \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}+70 \cot \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}-105 f x -210 \cot \left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{105 c^{4} f}\) | \(67\) |
derivativedivides | \(\frac {a^{3} \left (-\frac {1}{7 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{7}}+\frac {2}{5 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}-\frac {2}{3 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}}+\frac {2}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )}+2 \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )\right )}{f \,c^{4}}\) | \(76\) |
default | \(\frac {a^{3} \left (-\frac {1}{7 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{7}}+\frac {2}{5 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}-\frac {2}{3 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}}+\frac {2}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )}+2 \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )\right )}{f \,c^{4}}\) | \(76\) |
risch | \(\frac {a^{3} x}{c^{4}}+\frac {2 i a^{3} \left (735 \,{\mathrm e}^{6 i \left (f x +e \right )}-2520 \,{\mathrm e}^{5 i \left (f x +e \right )}+5635 \,{\mathrm e}^{4 i \left (f x +e \right )}-6160 \,{\mathrm e}^{3 i \left (f x +e \right )}+4557 \,{\mathrm e}^{2 i \left (f x +e \right )}-1624 \,{\mathrm e}^{i \left (f x +e \right )}+337\right )}{105 f \,c^{4} \left ({\mathrm e}^{i \left (f x +e \right )}-1\right )^{7}}\) | \(103\) |
norman | \(\frac {\frac {a^{3} x \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{7}}{c}+\frac {a^{3} x \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{11}}{c}-\frac {a^{3}}{7 c f}+\frac {24 a^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}}{35 c f}-\frac {169 a^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{4}}{105 c f}+\frac {56 a^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{6}}{15 c f}-\frac {14 a^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{8}}{3 c f}+\frac {2 a^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{10}}{c f}-\frac {2 a^{3} x \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{9}}{c}}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1\right )^{2} c^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{7}}\) | \(211\) |
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.29 \[ \int \frac {(a+a \sec (e+f x))^3}{(c-c \sec (e+f x))^4} \, dx=\frac {337 \, a^{3} \cos \left (f x + e\right )^{4} - 276 \, a^{3} \cos \left (f x + e\right )^{3} - 50 \, a^{3} \cos \left (f x + e\right )^{2} + 396 \, a^{3} \cos \left (f x + e\right ) - 167 \, a^{3} + 105 \, {\left (a^{3} f x \cos \left (f x + e\right )^{3} - 3 \, a^{3} f x \cos \left (f x + e\right )^{2} + 3 \, a^{3} f x \cos \left (f x + e\right ) - a^{3} f x\right )} \sin \left (f x + e\right )}{105 \, {\left (c^{4} f \cos \left (f x + e\right )^{3} - 3 \, c^{4} f \cos \left (f x + e\right )^{2} + 3 \, c^{4} f \cos \left (f x + e\right ) - c^{4} f\right )} \sin \left (f x + e\right )} \]
[In]
[Out]
\[ \int \frac {(a+a \sec (e+f x))^3}{(c-c \sec (e+f x))^4} \, dx=\frac {a^{3} \left (\int \frac {3 \sec {\left (e + f x \right )}}{\sec ^{4}{\left (e + f x \right )} - 4 \sec ^{3}{\left (e + f x \right )} + 6 \sec ^{2}{\left (e + f x \right )} - 4 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {3 \sec ^{2}{\left (e + f x \right )}}{\sec ^{4}{\left (e + f x \right )} - 4 \sec ^{3}{\left (e + f x \right )} + 6 \sec ^{2}{\left (e + f x \right )} - 4 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {\sec ^{3}{\left (e + f x \right )}}{\sec ^{4}{\left (e + f x \right )} - 4 \sec ^{3}{\left (e + f x \right )} + 6 \sec ^{2}{\left (e + f x \right )} - 4 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {1}{\sec ^{4}{\left (e + f x \right )} - 4 \sec ^{3}{\left (e + f x \right )} + 6 \sec ^{2}{\left (e + f x \right )} - 4 \sec {\left (e + f x \right )} + 1}\, dx\right )}{c^{4}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 383 vs. \(2 (117) = 234\).
Time = 0.34 (sec) , antiderivative size = 383, normalized size of antiderivative = 2.88 \[ \int \frac {(a+a \sec (e+f x))^3}{(c-c \sec (e+f x))^4} \, dx=\frac {5 \, a^{3} {\left (\frac {336 \, \arctan \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1}\right )}{c^{4}} + \frac {{\left (\frac {21 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} - \frac {77 \, \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} + \frac {315 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} - 3\right )} {\left (\cos \left (f x + e\right ) + 1\right )}^{7}}{c^{4} \sin \left (f x + e\right )^{7}}\right )} + \frac {3 \, a^{3} {\left (\frac {21 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + \frac {35 \, \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} - \frac {105 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} - 15\right )} {\left (\cos \left (f x + e\right ) + 1\right )}^{7}}{c^{4} \sin \left (f x + e\right )^{7}} + \frac {9 \, a^{3} {\left (\frac {21 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} - \frac {35 \, \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} + \frac {35 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} - 5\right )} {\left (\cos \left (f x + e\right ) + 1\right )}^{7}}{c^{4} \sin \left (f x + e\right )^{7}} - \frac {a^{3} {\left (\frac {21 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} - \frac {35 \, \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} - \frac {105 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} + 15\right )} {\left (\cos \left (f x + e\right ) + 1\right )}^{7}}{c^{4} \sin \left (f x + e\right )^{7}}}{840 \, f} \]
[In]
[Out]
none
Time = 0.36 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.66 \[ \int \frac {(a+a \sec (e+f x))^3}{(c-c \sec (e+f x))^4} \, dx=\frac {\frac {105 \, {\left (f x + e\right )} a^{3}}{c^{4}} + \frac {210 \, a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{6} - 70 \, a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{4} + 42 \, a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 15 \, a^{3}}{c^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{7}}}{105 \, f} \]
[In]
[Out]
Time = 14.80 (sec) , antiderivative size = 122, normalized size of antiderivative = 0.92 \[ \int \frac {(a+a \sec (e+f x))^3}{(c-c \sec (e+f x))^4} \, dx=\frac {a^3\,\left (-\frac {{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7}{7}+\frac {2\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2}{5}-\frac {2\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4}{3}+2\,\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6+\left (e+f\,x\right )\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7\right )}{c^4\,f\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7} \]
[In]
[Out]